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Chemical Equilibrium question

2023 · 6 Apr · Shift 2 · Q20
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Chemical Equilibrium question

2023 · 6 Apr · Shift 2 · Q20

JEE MainChemistryChemical EquilibriumNumerical+4 / −1
The equilibrium composition for the reaction PCl3+Cl2⇌PCl5\mathrm{PCl}_{3}+\mathrm{Cl}_{2} \rightleftharpoons \mathrm{PCl}_{5}PCl3​+Cl2​⇌PCl5​ at 298 K298 \mathrm{~K}298 K is given below: [PCl3]eq=0.2 mol L−1,[Cl2]eq=0.1 mol L−1,[PCl5]eq=0.40 mol L−1\left[\mathrm{PCl}_{3}\right]_{\mathrm{eq}}=0.2 \mathrm{~mol} \mathrm{~L}^{-1},\left[\mathrm{Cl}_{2}\right]_{\mathrm{eq}}=0.1 \mathrm{~mol} \mathrm{~L}^{-1},\left[\mathrm{PCl}_{5}\right]_{\mathrm{eq}}=0.40 \mathrm{~mol} \mathrm{~L}^{-1}[PCl3​]eq​=0.2 mol L−1,[Cl2​]eq​=0.1 mol L−1,[PCl5​]eq​=0.40 mol L−1 If 0.2 mol0.2 \mathrm{~mol}0.2 mol of Cl2\mathrm{Cl}_{2}Cl2​ is added at the same temperature, the equilibrium concentrations of PCl5\mathrm{PCl}_{5}PCl5​ is ‾\underline{\hspace{2cm}}​×10−2 mol L−1\times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}×10−2 mol L−1 Given : Kc\mathrm{K}_{\mathrm{c}}Kc​ for the reaction at 298 K298 \mathrm{~K}298 K is 20
Numerical answer
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