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Chemical Equilibrium question

2024 · 31 Jan · Shift 1 · Q12

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JEE Main
Chemistry
Chemical Equilibrium
2024 · 31 Jan · Shift 1 · Q12

Chemical Equilibrium question

2024 · 31 Jan · Shift 1 · Q12

JEE MainChemistryChemical EquilibriumMCQ+4 / −1

For the given reaction, choose the correct expression of

\mathrm{K}_{\mathrm{C}}

from the following :-

\mathrm{Fe}_{(\mathrm{aq})}^{3+}+\mathrm{SCN}_{(\mathrm{aq})}^{-} \rightleftharpoons(\mathrm{FeSCN})_{(\mathrm{aq})}^{2+}

A
$\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}{\left[\mathrm{FeSCN}^{2+}\right]}$
B
$\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}$
C
$\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]^2}{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}$
D
$\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right]^2\left[\mathrm{SCN}^{-}\right]^2}$

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