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Chemical Equilibrium question

2023 · 1 Feb · Shift 1 · Q20
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  5. /2023 · 1 Feb · Shift 1 · Q20

Chemical Equilibrium question

2023 · 1 Feb · Shift 1 · Q20

JEE MainChemistryChemical EquilibriumNumerical+4 / −1
(i) X(g)⇌Y(g)+Z(g)Kp1=3\mathrm{X}(\mathrm{g}) \rightleftharpoons \mathrm{Y}(\mathrm{g})+\mathrm{Z}(\mathrm{g}) \quad \mathrm{K}_{\mathrm{p} 1}=3X(g)⇌Y(g)+Z(g)Kp1​=3(ii) A(g)⇌2 B(g)Kp2=1\mathrm{A}(\mathrm{g}) \rightleftharpoons 2 \mathrm{~B}(\mathrm{g}) \quad \mathrm{K}_{\mathrm{p} 2}=1A(g)⇌2 B(g)Kp2​=1 If the degree of dissociation and initial concentration of both the reactants X(g)\mathrm{X}(\mathrm{g})X(g) and A(g)\mathrm{A}(\mathrm{g})A(g) are equal, then the ratio of the total pressure at equilibrium (p1p2)\left(\frac{p_{1}}{p_{2}}\right)(p2​p1​​) is equal to x:1\mathrm{x}: 1x:1. The value of x\mathrm{x}x is ‾\underline{\hspace{2cm}}​ (Nearest integer)
Numerical answer
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