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Chemical Equilibrium question

2024 · 29 Jan · Shift 1 · Q24

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JEE Main
Chemistry
Chemical Equilibrium
2024 · 29 Jan · Shift 1 · Q24

Chemical Equilibrium question

2024 · 29 Jan · Shift 1 · Q24

JEE MainChemistryChemical EquilibriumNumerical+4 / −1

For the reaction

\mathrm{N}_2 \mathrm{O}_{4(\mathrm{~g})} \rightleftarrows 2 \mathrm{NO}_{2(\mathrm{~g})}, \mathrm{K}_{\mathrm{p}}=0.492 \mathrm{~atm}

at

300 \mathrm{~K} . \mathrm{K}_{\mathrm{c}}

for the reaction at same temperature is

\underline{\hspace{2cm}}

\times 10^{-2}

. (Given :

\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}

)

Numerical answer

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