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Chemical Equilibrium question

2024 · 4 Apr · Shift 2 · Q17

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JEE Main
Chemistry
Chemical Equilibrium
2024 · 4 Apr · Shift 2 · Q17

Chemical Equilibrium question

2024 · 4 Apr · Shift 2 · Q17

JEE MainChemistryChemical EquilibriumMCQ+4 / −1

The equilibrium constant for the reaction

\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})

is

\mathrm{K}_{\mathrm{c}}=4.9 \times 10^{-2}

. The value of

\mathrm{K}_{\mathrm{c}}

for the reaction given below is

2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})

is :

A
49
B
416
C
41.6
D
4.9

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