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Chemical Bonding and Molecular Structure question

2024 · 8 Apr · Shift 2 · Q7
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Chemical Bonding and Molecular Structure question

2024 · 8 Apr · Shift 2 · Q7

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
When ψA\psi_{\mathrm{A}}ψA​ and ψB\psi_{\mathrm{B}}ψB​ are the wave functions of atomic orbitals, then σ∗\sigma^*σ∗ is represented by :
  1. A
    ψA+2ψB\psi_A+2 \psi_BψA​+2ψB​
  2. B
    ψA−ψB\psi_{\mathrm{A}}-\psi_{\mathrm{B}}ψA​−ψB​
  3. C
    ψA−2ψB\psi_A-2 \psi_BψA​−2ψB​
  4. D
    ψA+ψB\psi_{\mathrm{A}}+\psi_{\mathrm{B}}ψA​+ψB​
View written solutionFree

Correct answer: B

  1. In molecular orbital theory, when two atomic orbitals with wave functions ψA\psi_AψA​ and ψB\psi_BψB​ combine, they form:

    • Bonding molecular orbital by constructive interference: ψσ=ψA+ψB\psi_{\sigma}=\psi_A+\psi_Bψσ​=ψA​+ψB​

    • Antibonding molecular orbital by destructive interference: ψσ∗=ψA−ψB\psi_{\sigma^*}=\psi_A-\psi_Bψσ∗​=ψA​−ψB​

  2. The symbol σ∗\sigma^*σ∗ denotes the antibonding sigma molecular orbital.

  3. Therefore, its wave function is: σ∗∝ψA−ψB\sigma^* \propto \psi_A-\psi_Bσ∗∝ψA​−ψB​

  4. Now check the options:

    • A: ψA+2ψB\psi_A+2\psi_BψA​+2ψB​ — incorrect
    • B: ψA−ψB\psi_A-\psi_BψA​−ψB​ — correct
    • C: ψA−2ψB\psi_A-2\psi_BψA​−2ψB​ — incorrect
    • D: ψA+ψB\psi_A+\psi_BψA​+ψB​ — bonding, not antibonding

Hence, the correct answer is B.

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