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Chemical Bonding and Molecular Structure question

2003 · Shift 0 · Q64
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Chemical Bonding and Molecular Structure question

2003 · Shift 0 · Q64

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
The pair of species having identical shapes for molecules of both species is
  1. A
    XeF2XeF_2XeF2​, CO2CO_2CO2​
  2. B
    BF3BF_3BF3​, PCl3PCl_3PCl3​
  3. C
    PF5PF_5PF5​, IF5IF_5IF5​
  4. D
    CF4CF_4CF4​, SF4SF_4SF4​
View written solutionFree

Correct answer: A

  1. Determine the shape of each molecule using VSEPR theory

We compare the molecular shapes of both species in each option.

  1. Option A: XeF2XeF_2XeF2​ and CO2CO_2CO2​

  • XeF2XeF_2XeF2​

    • Central atom: Xe
    • Xe has 8 valence electrons.
    • It forms 2 bonds with F and has 3 lone pairs.
    • Total electron pairs around Xe =5= 5=5.
    • Electron pair geometry: trigonal bipyramidal
    • Lone pairs occupy equatorial positions, so the molecular shape is linear.

  • CO2CO_2CO2​

    • Central atom: C
    • Carbon forms 2 double bonds with oxygen.
    • Number of electron domains around C =2= 2=2.
    • Molecular shape: linear.

So both have identical shape: linear.

  1. Option B: BF3BF_3BF3​ and PCl3PCl_3PCl3​

  • BF3BF_3BF3​

    • Central atom: B
    • 3 bond pairs, 0 lone pairs
    • Shape: trigonal planar

  • PCl3PCl_3PCl3​

    • Central atom: P
    • 3 bond pairs, 1 lone pair
    • Shape: trigonal pyramidal

Shapes are not identical.

  1. Option C: PF5PF_5PF5​ and IF5IF_5IF5​

  • PF5PF_5PF5​

    • 5 bond pairs, 0 lone pairs
    • Shape: trigonal bipyramidal

  • IF5IF_5IF5​

    • 5 bond pairs, 1 lone pair
    • Electron pair geometry: octahedral
    • Molecular shape: square pyramidal

Shapes are not identical.

  1. Option D: CF4CF_4CF4​ and SF4SF_4SF4​

  • CF4CF_4CF4​

    • 4 bond pairs, 0 lone pairs
    • Shape: tetrahedral

  • SF4SF_4SF4​

    • 4 bond pairs, 1 lone pair
    • Electron pair geometry: trigonal bipyramidal
    • Molecular shape: seesaw

Shapes are not identical.

  1. Conclusion

Only Option A has both molecules with identical shape.

A: XeF2, CO2\boxed{\text{A: } XeF_2,\ CO_2}A: XeF2​, CO2​​

  1. Comparison with stored correct answer

Stored correct answer: A

My derived answer: A

They match.

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