Recall the structures and sources of the given carbohydrates

• Amylose: linear polymer of glucose with $\alpha(1\to 4)$ glycosidic linkage; found in plants (starch component).
• Cellulose: linear polymer of glucose with $\beta(1\to 4)$ glycosidic linkage; found in plants.
• Glycogen: branched polymer of glucose with $\alpha(1\to 4)$ main chain and $\alpha(1\to 6)$ शाख branching; found in animals.
• Amylopectin: branched polymer of glucose with $\alpha(1\to 4)$ main chain and $\alpha(1\to 6)$ branching; found in plants.

Match each with List-II

From List-II:

• (I) $\beta$-$C_1-C_4$, plant
• (II) $\alpha$-$C_1-C_4$, animal
• (III) $\alpha$-$C_1-C_4$, $\alpha$-$C_1-C_6$, plant
• (IV) $\alpha$-$C_1-C_4$, plant

Therefore,

• (A) Amylose $\to$ (IV)
• (B) Cellulose $\to$ (I)
• (C) Glycogen should be $\alpha(1\to4)$ and $\alpha(1\to6)$, animal
• (D) Amylopectin $\to$ (III)

Check the options

• Option D gives: $(A)-(IV),\ (B)-(I),\ (C)-(II),\ (D)-(III)$

Here, $(C)-(II)$ means glycogen is matched with $\alpha-C_1-C_4$, animal, but glycogen is actually branched with both $\alpha(1\to4)$ and $\alpha(1\to6)$ linkages.

Interpretation of the given list

Since List-II does not contain "${\alpha-C_1-C_4,\ \alpha-C_1-C_6,\ \text{animal}}$", the intended school-level matching likely uses:

• glycogen as the animal storage polysaccharide with predominant $\alpha(1\to4)$ chain,
• amylopectin as the plant branched polysaccharide with $\alpha(1\to4)$ and $\alpha(1\to6)$.

Under the given options, the only feasible match is: $(A)-(IV),\ (B)-(I),\ (C)-(II),\ (D)-(III)$ i.e. Option D.

Final answer

$\boxed{\text{D}}$