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Biomolecules question

2023 · 24 Jan · Shift 1 · Q17
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Biomolecules question

2023 · 24 Jan · Shift 1 · Q17

JEE MainChemistryBiomoleculesNumerical+4 / −1
Uracil is a base present in RNA with the following structure. % of N in uracil is ‾\underline{\hspace{2cm}}​ JEE Main 2023 (Online) 24th January Morning Shift Chemistry - Biomolecules Question 54 English Given: Molar mass N = 14 g mol −1^{-1}−1 O = 16 g mol −1^{-1}−1 C = 12 g mol −1^{-1}−1 H = 1 g mol −1^{-1}−1
Numerical answer
View written solutionFree

Correct answer: 25

  1. Identify the molecular formula of uracil
    From the given structure, uracil has formula: C4H4N2O2\mathrm{C_4H_4N_2O_2}C4​H4​N2​O2​

  2. Calculate molar mass of uracil
    Using the given atomic masses: Molar mass=4(12)+4(1)+2(14)+2(16)\text{Molar mass} = 4(12) + 4(1) + 2(14) + 2(16)Molar mass=4(12)+4(1)+2(14)+2(16) =48+4+28+32=112= 48 + 4 + 28 + 32 = 112=48+4+28+32=112

  3. Calculate mass of nitrogen in one mole of uracil
    There are 222 nitrogen atoms: Mass of N=2(14)=28\text{Mass of N} = 2(14) = 28Mass of N=2(14)=28

  4. Calculate percentage of nitrogen
    % of N=28112×100=25%\%\text{ of N} = \frac{28}{112} \times 100 = 25\%% of N=11228​×100=25%

  5. Final answer
    The percentage of nitrogen in uracil is: 25\boxed{25}25​

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