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Biomolecules question

2023 · 30 Jan · Shift 2 · Q16
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Biomolecules question

2023 · 30 Jan · Shift 2 · Q16

JEE MainChemistryBiomoleculesNumerical+4 / −1
A short peptide on complete hydrolysis produces 3 moles of glycine (G), two moles of leucine (L) and two moles of valine (V) per mole of peptide. The number of peptide linkages in it are ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 6

  1. Identify the total number of amino acid residues

The peptide gives on complete hydrolysis:

  • 333 moles of glycine
  • 222 moles of leucine
  • 222 moles of valine

So, total amino acid units in one molecule of peptide are: 3+2+2=73+2+2=73+2+2=7

Thus, the peptide contains 7 amino acid residues.

  1. Relation between amino acids and peptide linkages

If a peptide contains nnn amino acid residues in a single chain, then the number of peptide bonds (linkages) is: n−1n-1n−1

Here, n=7n=7n=7, so 7−1=67-1=67−1=6

  1. Final answer

The number of peptide linkages is: 6\boxed{6}6​

  1. Comparison with stored correct answer

Stored correct answer = 666

Our derived answer = 666

Hence, the answer agrees with the stored correct answer.

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