To solve this matching question, we identify the Haworth projection features of each sugar form.

1. Key rule for $\alpha$ and $\beta$ forms

For D-sugars in Haworth form:

• The terminal $\mathrm{CH_2OH}$ group is generally up.
• $\alpha$-anomer: anomeric $\mathrm{OH}$ is down.
• $\beta$-anomer: anomeric $\mathrm{OH}$ is up.

2. Identify anomeric carbon

• In glucose (an aldose), the anomeric carbon is C-1.
• In fructose (a ketose), the anomeric carbon is C-2.

3. Distinguish pyranose and furanose

• Glucopyranose has a six-membered ring.
• Fructofuranose has a five-membered ring.

So:

• Structures with 5-membered ring correspond to fructofuranose.
• Structures with 6-membered ring correspond to glucopyranose.

4. Match the four entries

Given Row I:

1. $\alpha$-D-$(-)$-Fructofuranose
2. $\beta$-D-$(-)$-Fructofuranose
3. $\alpha$-D-$(-)$-Glucopyranose
4. $\beta$-D-$(-)$-Glucopyranose

Now using the standard Haworth criteria:

• A must be $\alpha$-D-glucopyranose $\Rightarrow$ iii
• B must be $\beta$-D-glucopyranose $\Rightarrow$ iv
• C must be $\alpha$-D-fructofuranose $\Rightarrow$ i
• D must be $\beta$-D-fructofuranose $\Rightarrow$ ii

Thus the correct matching is: $A \to iii,\quad B \to iv,\quad C \to i,\quad D \to ii$

5. Compare with options

This corresponds to Option A.

6. Verification with stored answer

Stored correct answer = A

Our derived answer = A

Hence, they agree.