Write the structure from the IUPAC name

The parent chain is hex-1-en-4-yne:

• 6 carbon chain
• double bond between C1 and C2
• triple bond between C4 and C5
• at C3, there are two methyl groups

So the structure is:

$\mathrm{CH_2=CH-C(CH_3)_2-C\equiv C-CH_3}$

Now count the hybridisation of each carbon

Let us label all carbons:

• C1: $\mathrm{CH_2}$ in $\mathrm{C=C}$ $\Rightarrow \mathrm{sp^2}$
• C2: $\mathrm{CH}$ in $\mathrm{C=C}$ $\Rightarrow \mathrm{sp^2}$
• C3: central carbon attached by four single bonds $\Rightarrow \mathrm{sp^3}$
• C4: carbon in $\mathrm{C\equiv C}$ $\Rightarrow \mathrm{sp}$
• C5: carbon in $\mathrm{C\equiv C}$ $\Rightarrow \mathrm{sp}$
• C6: terminal $\mathrm{CH_3}$ attached by single bond $\Rightarrow \mathrm{sp^3}$
• Two methyl substituent carbons on C3: each has four single bonds $\Rightarrow \mathrm{sp^3, sp^3}$

Total count

• $\mathrm{sp^3}$ carbons: C3, C6, and two methyl carbons $=4$
• $\mathrm{sp^2}$ carbons: C1, C2 $=2$
• $\mathrm{sp}$ carbons: C4, C5 $=2$

Match with options

$\boxed{4,2,2}$

Hence, the correct option is A.