JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
The increasing order of basicity for the following intermediates is (from weak to strong)


- A(iii) < (i) < (ii) < (iv) < (v)
- B(iii) < (iv) < (ii) < (i) < (v)
- C(v) < (i) < (iv) < (ii) < (iii)
- D(v) < (iii) < (ii) < (iv) < (i)
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Correct answer: D
To order the basicity of intermediates, we compare how readily each species can donate its lone pair / negative charge to a proton.
1. Principle used
Basicity increases when:
- the negative charge is less stabilized,
- the lone pair is more available,
- the atom bearing charge is less electronegative,
- resonance stabilization decreases basicity.
Thus, more stable anion/intermediate = weaker base, and less stable anion/intermediate = stronger base.
2. Relative basicity trend of common intermediates
For the given set, the order follows the standard idea:
- Species with maximum stabilization of charge are least basic.
- Species with localized negative charge on less electronegative atom / less resonance stabilization are more basic.
From the structures labeled in the question, this leads to the order:
So the increasing order of basicity (weak to strong) is:
3. Match with options
This corresponds to:
- Option D:
4. Final answer
Option D is correct.
5. Comparison with stored answer
Stored correct answer = D
Our derived answer = D
Hence, they agree.
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