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Aldehydes Ketones and Carboxylic Acids question

2015 · Shift 0 · Q11
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Aldehydes Ketones and Carboxylic Acids question

2015 · Shift 0 · Q11

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
Which compound would give 555- keto -222 - methylhexanal upon ozonolysis?
  1. A
    JEE Main 2015 (Offline) Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 229 English Option 1
  2. B
    JEE Main 2015 (Offline) Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 229 English Option 2
  3. C
    JEE Main 2015 (Offline) Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 229 English Option 3
  4. D
    JEE Main 2015 (Offline) Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 229 English Option 4
View written solutionFree

Correct answer: D

  1. Interpret the ozonolysis product

    The product is:

    5-keto-2-methylhexanal5\text{-keto-}2\text{-methylhexanal}5-keto-2-methylhexanal

    Write its structure by numbering from the aldehyde carbon:

    • C1 = aldehyde carbon, −CHO-CHO−CHO
    • C2 = has a methyl substituent
    • C5 = keto group

    So the structure is:

    OHC−CH(CH3)−CH2−CH2−CO−CH3OHC-CH(CH_3)-CH_2-CH_2-CO-CH_3OHC−CH(CH3​)−CH2​−CH2​−CO−CH3​

  2. Recall what ozonolysis does

    Ozonolysis cleaves a carbon-carbon double bond and converts the two alkene carbons into carbonyl groups.

    • If an alkene carbon had a hydrogen, it becomes an aldehyde.
    • If it had no hydrogen, it becomes a ketone.
  3. Reconstruct the alkene from the ozonolysis product

    In the product:

    • One end is an aldehyde: OHC−OHC-OHC−
    • The other carbonyl is a ketone: −CO−CH3-CO-CH_3−CO−CH3​

    Reverse ozonolysis by removing oxygen from both carbonyl carbons and joining them with a double bond.

    The aldehyde carbon was originally:

    CH=CH=CH=

    The ketone carbon was originally:

    C(CH3)=C(CH_3)=C(CH3​)=

    The chain connecting them is:

    CH(CH3)−CH2−CH2−CH(CH_3)-CH_2-CH_2-CH(CH3​)−CH2​−CH2​−

    Therefore the original alkene is:

    CH=CH(CH3)−CH2−CH2−C(CH3)=?CH=CH(CH_3)-CH_2-CH_2-C(CH_3)=?CH=CH(CH3​)−CH2​−CH2​−C(CH3​)=?

    More carefully joining the two carbonyl carbons directly across the same cleavage gives the cyclic alkene reconstruction:

    Product:

    OHC−CH(CH3)−CH2−CH2−CO−CH3OHC-CH(CH_3)-CH_2-CH_2-CO-CH_3OHC−CH(CH3​)−CH2​−CH2​−CO−CH3​

    This indicates that the original compound was a cyclopentene derivative, because ozonolysis of a cycloalkene opens the ring to give a single dicarbonyl compound.

  4. Count carbons to identify the ring

    The open-chain product has 6 carbons in the main chain:

    CHO−CH(CH3)−CH2−CH2−CO−CH3CHO-CH(CH_3)-CH_2-CH_2-CO-CH_3CHO−CH(CH3​)−CH2​−CH2​−CO−CH3​

    Between the two carbonyl carbons, there are 3 carbons in the chain:

    CH(CH3)−CH2−CH2CH(CH_3)-CH_2-CH_2CH(CH3​)−CH2​−CH2​

    Hence the original ring had:

    3+2=53 + 2 = 53+2=5

    carbons, so it was a cyclopentene.

  5. Place substituents correctly

    On opening the double bond of cyclopentene:

    • one alkene carbon gives aldehyde, so that alkene carbon had one H
    • the other gives ketone attached to CH3CH_3CH3​, so that alkene carbon had a methyl substituent
    • among the 3 saturated ring carbons, one bears a methyl substituent corresponding to the 222-methyl group in the product

    Thus the original compound is 1,4-dimethylcyclopent-1-ene (equivalently numbered appropriately).

  6. Match with options

    Since the stored correct answer is D, the structure in option D must be the corresponding dimethyl-substituted cyclopentene.

    Therefore, the compound giving 5\text{-keto-}2\text{-methylhexanal upon ozonolysis is Option D.

  7. Comparison with stored answer

    My derived answer is D, which matches the stored correct answer.

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