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Aldehydes Ketones and Carboxylic Acids question

2011 · Shift 0 · Q13
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Aldehydes Ketones and Carboxylic Acids question

2011 · Shift 0 · Q13

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the above reaction is
  1. A
    2-Butanone
  2. B
    Ethyl chloride
  3. C
    Ethyl ethanoate
  4. D
    Diethyl ether
View written solutionFree

Correct answer: C

  1. Identify the reactants

    • Sodium ethoxide: C2H5ONa\mathrm{C_2H_5ONa}C2​H5​ONa
    • Ethanoyl chloride: CH3COCl\mathrm{CH_3COCl}CH3​COCl
  2. Nature of the reaction

    Ethanoyl chloride is an acid chloride, and sodium ethoxide provides the ethoxide ion C2H5O−\mathrm{C_2H_5O^-}C2​H5​O−, which acts as a nucleophile.

    Acid chlorides undergo nucleophilic acyl substitution with alkoxides to form esters.

  3. Write the reaction

    CH3COCl+C2H5ONa→CH3COOC2H5+NaCl\mathrm{CH_3COCl + C_2H_5ONa \rightarrow CH_3COOC_2H_5 + NaCl}CH3​COCl+C2​H5​ONa→CH3​COOC2​H5​+NaCl

  4. Identify the product

    The product CH3COOC2H5\mathrm{CH_3COOC_2H_5}CH3​COOC2​H5​ is ethyl ethanoate.

  5. Check the options

    • A: 2-Butanone — not formed
    • B: Ethyl chloride — not formed
    • C: Ethyl ethanoate — correct
    • D: Diethyl ether — not formed
  6. Final answer

    The compound produced is ethyl ethanoate.

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