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Vector Algebra question

2010 · Shift 2 · Q38
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  5. /2010 · Shift 2 · Q38

Vector Algebra question

2010 · Shift 2 · Q38

JEE AdvancedMathematicsVector AlgebraMCQ+4 / −1
Two adjacent sides of a parallelogram ABCDABCDABCD are given by AB→=2i^+10j^+11k^\overrightarrow {AB} = 2\widehat i + 10\widehat j + 11\widehat kAB=2i+10j​+11k and  AD→=−i^+2j^+2k^\,\overrightarrow {AD} = -\widehat i + 2\widehat j + 2\widehat kAD=−i+2j​+2k The side ADADAD is rotated by an acute angle α\alphaα in the plane of the parallelogram so that ADADAD becomes AD′.AD'.AD′. If AD′AD'AD′ makes a right angle with the side AB,AB,AB, then the cosine of the angle α\alphaα is given by
  1. A
    89{{8 \over 9}}98​
  2. B
    179{{{\sqrt {17} } \over 9}}917​​
  3. C
    19{{1 \over 9}}91​
  4. D
    459{{{4\sqrt 5 } \over 9}}945​​
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