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Probability question

2017 · Shift 1 · Q19
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  5. /2017 · Shift 1 · Q19

Probability question

2017 · Shift 1 · Q19

JEE AdvancedMathematicsProbabilityMultiple correct+4 / −1
Let X and Y be two events such that P(X)=13P(X) = {1 \over 3}P(X)=31​, P(X∣Y)=12P(X|Y) = {1 \over 2}P(X∣Y)=21​ and P(Y∣X)=25P(Y|X) = {2 \over 5}P(Y∣X)=52​. Then
  1. A
    P(Y)=415P(Y) = {4 \over {15}}P(Y)=154​
  2. B
    P(X′∣Y)=12P(X'|Y) = {1 \over 2}P(X′∣Y)=21​
  3. C
    P(X∪Y)=25P(X \cup Y) = {2 \over 5}P(X∪Y)=52​
  4. D
    P(X∩Y)=15P(X \cap Y) = {1 \over 5}P(X∩Y)=51​
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