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Probability question

2016 · Shift 1 · Q21

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PYQ Library
JEE Advanced
Mathematics
Probability
2016 · Shift 1 · Q21

Probability question

2016 · Shift 1 · Q21

JEE AdvancedMathematicsProbabilityMCQ+3 / −1

A computer producing factory has only two plants

{T_1}

and

{T_2}.

Plant

{T_1}

produces

20

% and plant

{T_2}

produces

80

% of the total computers produced.

7

% of computers produced in the factory turn out to be defective. It is known that

P

(computer turns out to be defective given that it is produced in plant

{T_1}

)

= 10P

(computer turns out to be defective given that it is produced in plant

{T_2}

), where

P(E)

denotes the probability of an event

E

. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant

{T_2}

is

A
${{36} \over {73}}$
B
${{47} \over {79}}$
C
${{78} \over {93}}$
D
${{75} \over {83}}$

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