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Differentiation question

2008 · Shift 2 · Q35
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Differentiation question

2008 · Shift 2 · Q35

JEE AdvancedMathematicsDifferentiationMCQ+3 / −1
Let g(x)=log⁡f(x)g(x) = \log f(x)g(x)=logf(x), where f(x)f(x)f(x) is a twice differentiable positive function on (0, ∞\infty∞) such that f(x+1)=xf(x)f(x + 1) = xf(x)f(x+1)=xf(x). Then for N = 1, 2, 3, ..., g′′(N+12)−g′′(12)=g''\left( {N + {1 \over 2}} \right) - g''\left( {{1 \over 2}} \right) =g′′(N+21​)−g′′(21​)=
  1. A
    −4{1+19+125+.......+1(2N−1)2}- 4\left\{ {1 + {1 \over 9} + {1 \over {25}} + ....... + {1 \over {{{\left( {2N - 1} \right)}^2}}}} \right\}−4{1+91​+251​+.......+(2N−1)21​}
  2. B
    4{1+19+125+.......+1(2N−1)2}4\left\{ {1 + {1 \over 9} + {1 \over {25}} + ....... + {1 \over {{{\left( {2N - 1} \right)}^2}}}} \right\}4{1+91​+251​+.......+(2N−1)21​}
  3. C
    −4{1+19+125+.......+1(2N+1)2}- 4\left\{ {1 + {1 \over 9} + {1 \over {25}} + ....... + {1 \over {{{\left( {2N + 1} \right)}^2}}}} \right\}−4{1+91​+251​+.......+(2N+1)21​}
  4. D
    4{1+19+125+.......+1(2N+1)2}4\left\{ {1 + {1 \over 9} + {1 \over {25}} + ....... + {1 \over {{{\left( {2N + 1} \right)}^2}}}} \right\}4{1+91​+251​+.......+(2N+1)21​}
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