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Differentiation question

2008 · Shift 1 · Q31
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  5. /2008 · Shift 1 · Q31

Differentiation question

2008 · Shift 1 · Q31

JEE AdvancedMathematicsDifferentiationMCQ+3 / −1
Consider the functions defined implicitly by the equation y3−3y+x=0y^3-3y+x=0y3−3y+x=0 on various intervals in the real line. If x∈(−∞,−2)∪(2,∞)x\in(-\infty,-2)\cup(2,\infty)x∈(−∞,−2)∪(2,∞), the equation implicitly defines a unique real valued differentiable function y=f(x)y=f(x)y=f(x). If x∈(−2,2)x\in(-2,2)x∈(−2,2), the equation implicitly defines a unique real valued differentiable function y=g(x)y=g(x)y=g(x) satisfying g(0)=0g(0)=0g(0)=0If f(−102)=22,f\left( { - 10\sqrt 2 } \right) = 2\sqrt 2 ,f(−102​)=22​, then f′′(−102)=f''\left( { - 10\sqrt 2 } \right) =f′′(−102​)=
  1. A
    427332{{4\sqrt 2 } \over {{7^3}{3^2}}}733242​​
  2. B
    −427332-{{4\sqrt 2 } \over {{7^3}{3^2}}}−733242​​
  3. C
    42733{{4\sqrt 2 } \over {{7^3}3}}73342​​
  4. D
    −42733-{{4\sqrt 2 } \over {{7^3}3}}−73342​​
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