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Differentiation question

2008 · Shift 2 · Q31
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  5. /2008 · Shift 2 · Q31

Differentiation question

2008 · Shift 2 · Q31

JEE AdvancedMathematicsDifferentiationMCQ+3 / −1
Consider the function f:(−∞,∞)→(−∞,∞)f:\left( { - \infty ,\infty } \right) \to \left( { - \infty ,\infty } \right)f:(−∞,∞)→(−∞,∞) defined by f(x)=x2−ax+1x2+ax+1,0<a<2.f\left( x \right) = {{{x^2} - ax + 1} \over {{x^2} + ax + 1}},0 \lt a \lt 2.f(x)=x2+ax+1x2−ax+1​,0<a<2.Which of the following is true?
  1. A
    (2+a)2f′′(1)+(2−a)2f′′(−1)=0{\left( {2 + a} \right)^2}f''\left( 1 \right) + {\left( {2 - a} \right)^2}f''\left( { - 1} \right) = 0(2+a)2f′′(1)+(2−a)2f′′(−1)=0
  2. B
    (2−a)2f′′(1)−(2+a)2f′′(−1)=0{\left( {2 - a} \right)^2}f''\left( 1 \right) - {\left( {2 + a} \right)^2}f''\left( { - 1} \right) = 0(2−a)2f′′(1)−(2+a)2f′′(−1)=0
  3. C
    f′(1)f′(−1)=(2−a)2f'\left( 1 \right)f'\left( { - 1} \right) = {\left( {2 - a} \right)^2}f′(1)f′(−1)=(2−a)2
  4. D
    f′(1)f′(−1)=−(2+a)2f'\left( 1 \right)f'\left( { - 1} \right) = -{\left( {2 + a} \right)^2}f′(1)f′(−1)=−(2+a)2
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