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Application of Integration question

2011 · Shift 2 · Q28
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  5. /2011 · Shift 2 · Q28

Application of Integration question

2011 · Shift 2 · Q28

JEE AdvancedMathematicsApplication of IntegrationMCQ+4 / −1
Let f ::: [−1,2]→[0,∞]\left[ { - 1,2} \right] \to \left[ {0,\infty } \right][−1,2]→[0,∞] be a continuous function such that f(x)=f(1−x)f\left( x \right) = f\left( {1 - x} \right)f(x)=f(1−x) for all x∈[−1,2]x \in \left[ { - 1,2} \right]x∈[−1,2] Let R1=∫−12xf(x)dx,{R_1} = \int\limits_{ - 1}^2 {xf\left( x \right)dx,}R1​=−1∫2​xf(x)dx, and R2{R_2}R2​ be the area of the region bounded by y=f(x),x=−1,x=2,y=f(x),x=-1,x=2,y=f(x),x=−1,x=2, and the xxx-axis. Then
  1. A
    R1=2R2{R_1} = 2{R_2}R1​=2R2​
  2. B
    R1=3R2{R_1} = 3{R_2}R1​=3R2​
  3. C
    2R1=R2{2R_1} = {R_2}2R1​=R2​
  4. D
    3R1=R2{3R_1} = {R_2}3R1​=R2​
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