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Salt Analysis question

2021 · Shift 2 · Q15

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JEE Advanced
Chemistry
Salt Analysis
2021 · Shift 2 · Q15

Salt Analysis question

2021 · Shift 2 · Q15

JEE AdvancedChemistrySalt AnalysisMCQ+3 / −1

The reaction of

K_3[Fe(CN)_6]

with freshly prepared

FeSO_4

solution produces a dark blue precipitate called Turnbull's blue. Reaction of

K_4[Fe(CN)_6]

with the

FeSO_4

solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the

FeSO_4

solution with

NaNO_3

, followed by a slow addition of concentrated

H_2SO_4

through the side of the test tube produces a brown ring.Precipitate X is

A
$Fe_4[Fe(CN)_6]_3$
B
Fe[Fe(CN) ${}_6$ ]
C
$K_2Fe[Fe(CN)_6]$
D
KFe[Fe(CN) ${}_6$ ]

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