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Isolation of Elements question

2022 · Shift 1 · Q11
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Isolation of Elements question

2022 · Shift 1 · Q11

JEE AdvancedChemistryIsolation of ElementsMultiple correct+4 / −2
The electrochemical extraction of aluminum from bauxite ore involves
  1. A
    the reaction of Al2O3\mathrm{Al}_{2} \mathrm{O}_{3}Al2​O3​ with coke (C)(\mathrm{C})(C) at a temperature >2500∘C\gt 2500^{\circ} \mathrm{C}>2500∘C.
  2. B
    the neutralization of aluminate solution by passing CO2\mathrm{CO}_{2}CO2​ gas to precipitate hydrated alumina (Al2O3⋅3H2O)\left(\mathrm{Al}_{2} \mathrm{O}_{3} \cdot 3 \mathrm{H}_{2} \mathrm{O}\right)(Al2​O3​⋅3H2​O).
  3. C
    the dissolution of Al2O3\mathrm{Al}_{2} \mathrm{O}_{3}Al2​O3​ in hot aqueous NaOH\mathrm{NaOH}NaOH.
  4. D
    the electrolysis of Al2O3\mathrm{Al}_{2} \mathrm{O}_{3}Al2​O3​ mixed with Na3AlF6\mathrm{Na}_{3} \mathrm{AlF}_{6}Na3​AlF6​ to give Al\mathrm{Al}Al and CO2\mathrm{CO}_{2}CO2​.
View written solutionFree

Correct answer: B, D, C

  1. Identify the processes involved in extraction of aluminium from bauxite

    Extraction of aluminium from bauxite mainly involves:

    • Purification of bauxite by Bayer process
    • Electrolytic reduction of alumina by Hall–Héroult process
  2. Check each option one by one

    Option A

    "the reaction of Al2O3\mathrm{Al_2O_3}Al2​O3​ with coke (C)(\mathrm C)(C) at a temperature >2500∘C>2500^\circ\mathrm C>2500∘C"

    This is not used for extraction of aluminium.

    Reason: Al2O3\mathrm{Al_2O_3}Al2​O3​ is a very stable oxide and cannot be reduced by carbon in the usual metallurgical way. In fact, at such high temperatures, carbide formation may occur instead of obtaining pure aluminium.

    So, A is incorrect.


    Option B

    "the neutralization of aluminate solution by passing CO2\mathrm{CO_2}CO2​ gas to precipitate hydrated alumina (Al2O3⋅3H2O)\left(\mathrm{Al_2O_3\cdot 3H_2O}\right)(Al2​O3​⋅3H2​O)"

    In Bayer process, bauxite is digested with hot aqueous NaOH to form sodium aluminate solution. From this aluminate solution, hydrated alumina is precipitated.

    One way to represent precipitation is by passing CO2\mathrm{CO_2}CO2​: 2NaAlO2+CO2+3H2O→Al2O3⋅3H2O+Na2CO32\mathrm{NaAlO_2}+\mathrm{CO_2}+3\mathrm{H_2O}\rightarrow \mathrm{Al_2O_3\cdot 3H_2O}+\mathrm{Na_2CO_3}2NaAlO2​+CO2​+3H2​O→Al2​O3​⋅3H2​O+Na2​CO3​

    Thus, this step is involved in extraction/purification.

    So, B is correct.


    Option C

    "the dissolution of Al2O3\mathrm{Al_2O_3}Al2​O3​ in hot aqueous NaOH\mathrm{NaOH}NaOH"

    In Bayer process, alumina present in bauxite dissolves in hot concentrated NaOH due to amphoteric nature: Al2O3+2NaOH+3H2O→2Na[Al(OH)4]\mathrm{Al_2O_3}+2\mathrm{NaOH}+3\mathrm{H_2O}\rightarrow 2\mathrm{Na[Al(OH)_4]}Al2​O3​+2NaOH+3H2​O→2Na[Al(OH)4​] or equivalently as sodium aluminate formation.

    Hence this is indeed part of aluminium extraction.

    So, C is correct.


    Option D

    "the electrolysis of Al2O3\mathrm{Al_2O_3}Al2​O3​ mixed with Na3AlF6\mathrm{Na_3AlF_6}Na3​AlF6​ to give Al\mathrm{Al}Al and CO2\mathrm{CO_2}CO2​"

    In Hall–Héroult process, alumina is dissolved in molten cryolite (Na3AlF6)\left(\mathrm{Na_3AlF_6}\right)(Na3​AlF6​) and electrolysed.

    Cathode reaction: Al3++3e−→Al\mathrm{Al^{3+}}+3e^-\rightarrow \mathrm{Al}Al3++3e−→Al

    Oxygen formed at the anode reacts with carbon anodes: C+O2→CO2\mathrm{C}+\mathrm{O_2}\rightarrow \mathrm{CO_2}C+O2​→CO2​

    Therefore overall aluminium is obtained and CO2\mathrm{CO_2}CO2​ is produced.

    So, D is correct.

  3. Final derived answer

    Correct options are: B, C, D\boxed{B,\ C,\ D}B, C, D​

  4. Comparison with stored correct answer

    Stored correct answer: B, D, C

    This matches exactly with the derived set of correct options.

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