- AQ is
- BZ is [Zn(CN)]
- CT is Zn
- DR is [Au(CN)]
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Correct answer: A, B, C
The problem describes the MacArthur-Forrest cyanide process for the extraction of gold. We need to identify the reagents and products involved in the two main steps of this process.
Step 1: Leaching of Gold
The first step involves leaching the gold ore with a dilute solution of sodium cyanide (NaCN) or potassium cyanide (KCN). This is an oxidation process where gold is converted into a soluble complex. An oxidizing agent is required for this reaction, which is typically oxygen from the air.
The balanced chemical equation for this step is:
According to the question, gold is leached with CN in the presence of Q to form R.
- Comparing this with the reaction, the substance present along with CN is oxygen. Therefore, Q is O.
- The soluble complex formed is the dicyanoaurate(I) ion. Therefore, R is [Au(CN)].
Step 2: Precipitation of Gold
The second step is the recovery of gold from the soluble complex solution. This is done by a displacement reaction using a more electropositive metal, typically zinc (Zn). Zinc reduces the gold complex, causing metallic gold to precipitate out.
The balanced chemical equation for this step is:
According to the question, R is treated with T to obtain Au and Z.
- We identified R as . It is treated with zinc metal. Therefore, T is Zn.
- The products are metallic gold (Au) and a soluble zinc complex. Therefore, Z is [Zn(CN)].
Step 3: Evaluating the Options
Now we evaluate each option based on our findings:
- A: Q is O. This is correct. Oxygen acts as the oxidizing agent in the leaching step.
- B: Z is [Zn(CN)]. This is correct. Zinc forms the stable tetracyanozincate(II) complex.
- C: T is Zn. This is correct. Zinc metal is the reducing agent used to displace gold.
- D: R is [Au(CN)]. This is incorrect. The stable complex formed by Gold(I) with cyanide is the linear dicyanoaurate(I) ion, . The coordination number is 2, not 4.
Therefore, the correct options are A, B, and C.
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