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Isolation of Elements question

2012 · Shift 2 · Q1
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Isolation of Elements question

2012 · Shift 2 · Q1

JEE AdvancedChemistryIsolation of ElementsMCQ+2 / −0.5
In the cyanide extraction process of silver from argentite ore, the oxidising and reducing agents used are
  1. A
    O2O_2O2​ and COCOCO respectively
  2. B
    O2O_2O2​ and ZnZnZn dust respectively
  3. C
    HNO3HNO_3HNO3​ and ZnZnZn dust respectively
  4. D
    HNO3HNO_3HNO3​ and COCOCO respectively
View written solutionFree

Correct answer: B

  1. Identify the process involved

    In the cyanide extraction of silver from argentite ore Ag2S,\text{Ag}_2\text{S},Ag2​S, silver is first leached with a cyanide solution in the presence of oxygen.

  2. Leaching reaction

    The silver sulphide reacts with sodium cyanide and oxygen to form the soluble argentocyanide complex: Ag2S+4NaCN→2Na[Ag(CN)2]+Na2S\text{Ag}_2\text{S} + 4\text{NaCN} \rightarrow 2\text{Na}[\text{Ag}(\text{CN})_2] + \text{Na}_2\text{S}Ag2​S+4NaCN→2Na[Ag(CN)2​]+Na2​S In practice, oxygen helps in the oxidation process during dissolution. Hence, the oxidising agent is O2O_2O2​.

  3. Recovery of silver from the complex

    Silver is then displaced from the cyanide complex by adding zinc dust: 2Na[Ag(CN)2]+Zn→Na2[Zn(CN)4]+2Ag2\text{Na}[\text{Ag}(\text{CN})_2] + \text{Zn} \rightarrow \text{Na}_2[\text{Zn}(\text{CN})_4] + 2\text{Ag}2Na[Ag(CN)2​]+Zn→Na2​[Zn(CN)4​]+2Ag

    Here, zinc loses electrons and reduces silver ion/complex to metallic silver. Therefore, zinc acts as the reducing agent.

  4. Evaluate the options

    • A: O2O_2O2​ and COCOCO — incorrect, COCOCO is not used here.
    • B: O2O_2O2​ and ZnZnZn dust — correct.
    • C: HNO3HNO_3HNO3​ and ZnZnZn dust — incorrect, HNO3HNO_3HNO3​ is not the oxidising agent in cyanide extraction.
    • D: HNO3HNO_3HNO3​ and COCOCO — incorrect.
  5. Final answer

    The oxidising and reducing agents used are: O2 and Zn dust respectively.O_2 \text{ and Zn dust respectively}.O2​ and Zn dust respectively.

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