NEETPhysicsProperties of MatterMCQ+4 / −1
A small hole of area of cross-section 2 mm2 present near the bottom of a fully filled open tank of height 2 m. Taking g = 10 m/s2, the rate of flow of water through the open hole would be nearly :
- A8.9 × 10–6 m3/s
- B2.23 × 10–6 m3/s
- C6.4 × 10–6 m3/s
- D12.6 × 10–6 m3/s
View written solutionFree
Correct answer: D
volume flow rate = Av = A
= 2 10-6
= 2 2 3.14 10-6 m3/s
= 12.56 10-6 m3/s
= 12.6 10-6 m3/s
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