The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

Oscillations question

2007 · Q146

Oscillations question

2007 · Q146

View written solutionFree

Correct answer: D

Let y = Asin $\omega$ t

${{dy} \over {dt}} = A\omega \cos \omega t = A\omega \sin \left( {\omega t + {\pi \over 2}} \right)$

Acceleration = $- A{\omega ^2}\sin \omega t$

The phase difference between acceleration and velocity is $\pi /2$ .

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Oscillations question

2007 · Q146

Oscillations question

2007 · Q146

View written solutionFree

Correct answer: D

Let y = Asin $\omega$ t

${{dy} \over {dt}} = A\omega \cos \omega t = A\omega \sin \left( {\omega t + {\pi \over 2}} \right)$

Acceleration = $- A{\omega ^2}\sin \omega t$

The phase difference between acceleration and velocity is $\pi /2$ .