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Oscillations question

2003 · Q168
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Oscillations question

2003 · Q168

NEETPhysicsOscillationsMCQ+4 / −1
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is
  1. A
    23{2 \over 3}32​E
  2. B
    18{1 \over 8}81​E
  3. C
    14{1 \over 4}41​E
  4. D
    12{1 \over 2}21​E
View written solutionFree

Correct answer: C

Potential energy of simple harmonic oscillator = 12mω2y2{1 \over 2}m{\omega ^2}{y^2}21​mω2y2

for y=a2,P.E=12mω2a24y = {a \over 2},P.E = {1 \over 2}m{\omega ^2}{{{a^2}} \over 4}y=2a​,P.E=21​mω24a2​

⇒P.E=14(12mω2a2)=E4 \Rightarrow P.E = {1 \over 4}\left( {{1 \over 2}m{\omega ^2}{a^2}} \right) = {E \over 4}⇒P.E=41​(21​mω2a2)=4E​

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