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Oscillations question

2007 · Q145
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Oscillations question

2007 · Q145

NEETPhysicsOscillationsMCQ+4 / −1
The particle executing simple harmonic motion has a kinetic energy K0cos2ω\omegaωt. The maximum values of the potential energy and the total energy are respectively
  1. A
    K0/2 and K0
  2. B
    K0 and 2K0
  3. C
    K0 and K0
  4. D
    0 and 2k0
View written solutionFree

Correct answer: C

Kinetic energy + potential energy = total energy
When kinetic energy is maximum, potential energy is zero and vice versa.

∴\therefore∴ Maximum potential energy = total energy.

0 + K0 = K0 (K.E. + P.E. = total energy).

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