NEETPhysicsOscillationsMCQ+4 / −1
A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph
- A

- B

- C

- D

View written solutionFree
Correct answer: A
Potential energy of particle performing SHM varies parabolically in such a way that at mean position it becomes zero and maximum at extreme position.
More from Oscillations
- In case of a forced vibration, the resonance peak becomes very sharp when the2003 · MCQ
- The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be2003 · MCQ
- Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing simple harmonic motion is2002 · MCQ
- When an oscillator completes 100 oscillations its amplitude reduced to of initial value. What will be its amplitude, when it complettes 200 oscillations ?2002 · MCQ
- A mass is suspended separately by two different springs in (successive order then time periods is t1 and t2 respectively, If it is connected by both spring as shown in figure then time period is t0 , the correct relation is Includes diagram2002 · MCQ
- The total energy of particle performing SHM depend on2001 · MCQ
- Two masses A and B are hung from two strings of length A and B respectively. They are executing SHM with frequency relation A = 2B, then relation2000 · MCQ
- The bob of simple pendulum having length , is displaced from mean position to an angular position q with respect to vertical. If it is released, then velocity of bob at equilibrium position2000 · MCQ