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Oscillations question

2003 · Q171
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Oscillations question

2003 · Q171

NEETPhysicsOscillationsMCQ+4 / −1
The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be
  1. A
    T/4
  2. B
    T
  3. C
    T/2
  4. D
    2T
View written solutionFree

Correct answer: C

Let k be the force constant of spring. If k' is the force constant of each part, then

1l=4k′⇒k′=4k{1 \over l} = {4 \over {k'}} \Rightarrow k' = 4kl1​=k′4​⇒k′=4k

∴\therefore∴ Time period
= 2πm4k=12×2πmk=T22\pi \sqrt {{m \over {4k}}} = {1 \over 2} \times 2\pi \sqrt {{m \over k}} = {T \over 2}2π4km​​=21​×2πkm​​=2T​

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