Two very long, straight, parallel conductors A and B carry current of 5 A and 10 A respectively and are at a distance of 10 cm from each other. The direction of current in two conductors is same. The force acting per unit length between two conductors is : ( \mu 0 = 4 \pi \times 10 - 7 SI unit)

1 \times 10 - 4 Nm - 1 and is attractive

1 \times 10 - 4 Nm - 1 and is repulsive

2 \times 10 - 4 Nm - 1 and is attractive

2 \times 10 - 4 Nm - 1 and is repulsive

Moving Charges and Magnetism question

2022 · Q173

2022 · Q173

View written solutionFree

Correct answer: D

Force per unit length between two long current carrying wires $$ = {{{\mu _0}{l_1}{l_2}} \over {2\pi d}}$$

$$F = {{4\pi \times {{10}^{ - 7}} \times 5 \times 10} \over {2\pi \times 10 \times {{10}^{ - 2}}}} = {10^{ - 4}}$$ Nm^$-$1

$\Rightarrow$ The force is attractive as direction of current in two conductors is same

Hence, required force is $1 \times {10^{ - 4}}$ Nm^$-$1 and it is attractive.

2022 · Q173

2022 · Q173

View written solutionFree

Correct answer: D

Force per unit length between two long current carrying wires $$ = {{{\mu _0}{l_1}{l_2}} \over {2\pi d}}$$

$$F = {{4\pi \times {{10}^{ - 7}} \times 5 \times 10} \over {2\pi \times 10 \times {{10}^{ - 2}}}} = {10^{ - 4}}$$ Nm^$-$1

$\Rightarrow$ The force is attractive as direction of current in two conductors is same

Hence, required force is $1 \times {10^{ - 4}}$ Nm^$-$1 and it is attractive.