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Moving Charges and Magnetism question

2000 · Q131
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Moving Charges and Magnetism question

2000 · Q131

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1
The magnetic field at centre, P will be

AIPMT 2000 Physics - Moving Charges and Magnetism Question 25 English
  1. A
    μ04π{{{\mu _0}} \over {4\pi }}4πμ0​​
  2. B
    μ0π{{{\mu _0}} \over {\pi }}πμ0​​
  3. C
    μ02π{{{\mu _0}} \over {2\pi }}2πμ0​​
  4. D
    4μ0π4{\mu _0}\pi4μ0​π
View written solutionFree

Correct answer: C

Magnetic field due to 5A = 5μ02π×2.5{{5{\mu _0}} \over {2\pi \times 2.5}}2π×2.55μ0​​ = 2μ02π⊗{{2{\mu _0}} \over {2\pi }} \otimes 2π2μ0​​⊗

Magnetic field due to 2.5A = 2.5μ02π×2.5{{2.5{\mu _0}} \over {2\pi \times 2.5}}2π×2.52.5μ0​​ = μ02π⊙{{{\mu _0}} \over {2\pi }} \odot 2πμ0​​⊙

Resultant Magnetic field = 2μ02π−μ02π=μ02π⊗{{2{\mu _0}} \over {2\pi }} - {{{\mu _0}} \over {2\pi }} = {{{\mu _0}} \over {2\pi }} \otimes 2π2μ0​​−2πμ0​​=2πμ0​​⊗

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