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Moving Charges and Magnetism question

2024 · Q158
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Moving Charges and Magnetism question

2024 · Q158

NEETPhysicsMoving Charges and MagnetismMCQ+4 / −1

A tightly wound 100 turns coil of radius 10 cm10 \mathrm{~cm}10 cm carries a current of 7 A7 \mathrm{~A}7 A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10−7SI4 \pi \times 10^{-7} \mathrm{SI}4π×10−7SI units):

  1. A
    44 mT
  2. B
    4.4 T
  3. C
    4.4 mT
  4. D
    44 T
View written solutionFree

Correct answer: C

The magnitude of magnetic field due to circular coil of N turns is given by

$$ \begin{aligned} & B_C=\frac{\mu_0 i N}{2 R} \\ & =\frac{4 \pi \times 10^{-7} \times 7 \times 100}{2 \times 0.1} \\ & =4.4 \times 10^{-3} \mathrm{~T} \\ & =4.4 \mathrm{~mT} \end{aligned} $$

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