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Motion in A Straight Line question

2013 · Q142
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Motion in A Straight Line question

2013 · Q142

NEETPhysicsMotion in A Straight LineMCQ+4 / −1
A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is
  1. A
    h2 = 3h1 and h3 = 3h2
  2. B
    h1 = h2 = h3
  3. C
    h1 = 2h2 = 3h3
  4. D
    h1{h_1}h1​ = h23{{{h_2}} \over 3}3h2​​ = h35{{{h_3}} \over 5}5h3​​
View written solutionFree

Correct answer: D

NEET 2013 Physics - Motion in a Straight Line Question 35 English Explanation


Here h = ${1 \over 2}g{t^2}$

$ \therefore $ h1 = $${1 \over 2}g{\left( 5 \right)^2}$$ = 125

h1 + h2 = $${1 \over 2}g{\left( 10 \right)^2}$$ = 500

$ \Rightarrow $ h2 = 375

h1 + h2 + h3 = $${1 \over 2}g{\left( 15 \right)^2}$$ = 1125

$ \Rightarrow $ h3 = 625

$ \therefore $ h2 = 3h1 and h3 = 5h1

or ${h_1}$ = ${{{h_2}} \over 3}$ = ${{{h_3}} \over 5}$
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