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Motion in A Straight Line question

2008 · Q147
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Motion in A Straight Line question

2008 · Q147

NEETPhysicsMotion in A Straight LineMCQ+4 / −1
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms−-−1 to 20 ms−-−1 while passing through a distance 135 m in t second. The value of t is
  1. A
    12
  2. B
    9
  3. C
    10
  4. D
    1.8
View written solutionFree

Correct answer: B

v2 = u2 + 2aaas

⇒\Rightarrow⇒ a=v2−u22sa = {{{v^2} - {u^2}} \over {2s}}a=2sv2−u2​

         = (20)2−(10)22×135{{{{\left( {20} \right)}^2} - {{\left( {10} \right)}^2}} \over {2 \times 135}}2×135(20)2−(10)2​

         = 400−100270{{400 - 100} \over {270}}270400−100​

         = 300270{{300} \over {270}}270300​

         = 109{{10} \over 9}910​ m/s2

v=u+atv = u + atv=u+at

⇒\Rightarrow⇒ t=v−uat = {{v - u} \over a}t=av−u​

= 20−10109{{20 - 10} \over {{{10} \over 9}}}910​20−10​

= 10109{{10} \over {{{10} \over 9}}}910​10​ = 9 m/s

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