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Motion in A Straight Line question

2009 · Q154
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Motion in A Straight Line question

2009 · Q154

NEETPhysicsMotion in A Straight LineMCQ+4 / −1
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then
  1. A
    S2 = 3S1
  2. B
    S2 = 4S1
  3. C
    S2 = S1
  4. D
    S2 = 2S1
View written solutionFree

Correct answer: B

Given u = 0.

S1 = 12×a×t12{1 \over 2} \times a \times t_1^221​×a×t12​

and S2 = 12×a×t22{1 \over 2} \times a \times t_2^221​×a×t22​

S1S2=(t1t2)2{{{S_1}} \over {{S_2}}} = {\left( {{{{t_1}} \over {{t_2}}}} \right)^2}S2​S1​​=(t2​t1​​)2 = (1020)2{\left( {{{10} \over {20}}} \right)^2}(2010​)2 = 14{1 \over 4}41​

S2 = 4S1

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