NEETPhysicsMotion in A PlaneMCQ+4 / −1
A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30 above the horizontal. The maximum height attained by the ball during its motion is
(g = 10 m/s2)
- A25 m
- B5 m
- C10 m
- D20 m
View written solutionFree
Correct answer: B

Maximum height reached by the ball
$$H = {{{v^2}{{\sin }^2}\theta } \over {2g}}$$
$$ = {{{{(20)}^2}{{\sin }^2}30^\circ } \over {2g}}$$
$H = 5\,m$
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