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Motion in A Plane question

2021 · Q173
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Motion in A Plane question

2021 · Q173

NEETPhysicsMotion in A PlaneMCQ+4 / −1
A car starts from rest and accelerates at 5m/s2. At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s2)
  1. A
    202\sqrt 22​ m/s, 10 m/s2
  2. B
    20 m/s, 5 m/s2
  3. C
    20 m/s, 0
  4. D
    202\sqrt 22​ m/s, 0
View written solutionFree

Correct answer: A

u = 0

a = 5

t = 4

velocity of car at t = 4 sec is

V = u + at

V = 0 + 5 ×\times× 4

V = 20 m/s

For ball :

At t = 4 s, A ball is dropped out of a window so velocity of ball at this instant is 20 ms–1 along horizontal.

After 2 seconds of motion :



Horizontal velocity of ball , Vx = 20 m/sec

Vy = u + ut

= 10 ×\times× 2

Vertical velocity of ball, Vy = 20 m/sec

So magnitude of velocity of ball

V = Vx2+Vy2\sqrt {V_x^2 + V_y^2} Vx2​+Vy2​​ = 202\sqrt 2 2​

and Acceleration of ball at t = 6 s is g = 10 m/sec2 As ball is under free fall.

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