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Motion in A Plane question

2019 · Q129

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Physics
Motion in A Plane
2019 · Q129

Motion in A Plane question

2019 · Q129

NEETPhysicsMotion in A PlaneMCQ+4 / −1

When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60^o with horizontal, it can travel a distance x₁ along the plane. But when the inclination is decreased to 30^o and the same object is shot with the same velocity, it can travel x₂ distance. Then x₁ : x₂ will be :

A
1 : $\sqrt 2$
B
$\sqrt 2$ : 1
C
1 : $\sqrt 3$
D
1 : 2 $\sqrt 3$

View written solutionFree

Correct answer: C

Assume initial velocity = u

NEET 2019 Physics - Motion in a Plane Question 12 English Explanation 1

NEET 2019 Physics - Motion in a Plane Question 12 English Explanation 2

In first case, Moved distance, (x₁) =

{{{u^2}} \over {2g\sin {{60}^o}}}

In second case, Moved distance, (x₂) =

{{{u^2}} \over {2g\sin {{30}^o}}}

\therefore

{{{x_1}} \over {{x_2}}} = {{\sin {{30}^o}} \over {\sin {{60}^o}}}

=

{{1 \times 2} \over {2 \times \sqrt 3 }}

=

{1 \over {\sqrt 3 }}

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