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Motion in A Plane question

2010 · Q167
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Motion in A Plane question

2010 · Q167

NEETPhysicsMotion in A PlaneMCQ+4 / −1
A particle has initial velocity (3i^+4j^)\left( {3\widehat i + 4\widehat j} \right)(3i+4j​) and has acceleration (0.4j^+0.3j^).\left( {0.4\widehat j + 0.3\widehat j} \right).(0.4j​+0.3j​). Its speed after 10 s is
  1. A
    7 units
  2. B
    727\sqrt 272​ units
  3. C
    8.5 units
  4. D
    10 units
View written solutionFree

Correct answer: B

u→=3i^+4j^\overrightarrow u = 3\widehat i + 4\widehat ju=3i+4j​,  a→=0.4i^+0.3j^\overrightarrow a = 0.4\widehat i + 0.3\widehat ja=0.4i+0.3j​

⇒ux=3 units, uy=4 units \Rightarrow {u_x} = 3\,units,\,{u_y} = 4\,units⇒ux​=3units,uy​=4units

ax=0.4 units, ay=0.3 units{a_x} = 0.4\,units,\,{a_y} = 0.3\,unitsax​=0.4units,ay​=0.3units

∴\therefore∴ vx = ux + ax ×\times× 10 = 3 + 4 = 7 units

and vy = 4 + 0.3 ×\times× 10 = 4 + 3 = 7 units

∴v=vx2+vy2=72 \therefore v = \sqrt {v_x^2 + v_y^2} = 7\sqrt 2∴v=vx2​+vy2​​=72​ units

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