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Motion in A Plane question

2007 · Q132
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Motion in A Plane question

2007 · Q132

NEETPhysicsMotion in A PlaneMCQ+4 / −1
A→\overrightarrow AA and B→\overrightarrow BB are two vectors and θ\thetaθ is the angle between them, if ∣A→×B→∣=3(A→.B→),\left| {\overrightarrow A \times \overrightarrow B } \right| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } \right),​A×B​=3​(A.B), the value of θ\thetaθ is
  1. A
    45o
  2. B
    30o
  3. C
    90o
  4. D
    60o
View written solutionFree

Correct answer: D

∣A→×B→∣=3(A→.B→)\left| {\overrightarrow A \times \overrightarrow B } \right| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } \right)​A×B​=3​(A.B)

∴\therefore∴ ABsin⁡θ=3ABcos⁡θAB\sin \theta = \sqrt 3 AB\cos \theta ABsinθ=3​ABcosθ

or tan⁡θ=3\tan \theta = \sqrt 3 tanθ=3​ or θ=tan⁡−13=60∘\theta = {\tan ^{ - 1}}\sqrt 3 = 60^\circ θ=tan−13​=60∘;

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