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Motion in A Plane question

2006 · Q155
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Motion in A Plane question

2006 · Q155

NEETPhysicsMotion in A PlaneMCQ+4 / −1
For angles of projection of a projectile at angle (45o −-− θ\thetaθ) and (45o + θ\thetaθ), the horizontal range described by the projectile are in the ratio of
  1. A
    2 : 1
  2. B
    1 : 1
  3. C
    2 : 3
  4. D
    1 : 2.
View written solutionFree

Correct answer: B

(45º – θ\theta θ) & (45º + θ\theta θ) are complementary angles as 45º – θ\theta θ + 45º + θ\theta θ = 90º. We know that if angle of projection of two projectiles make complementary angles, their ranges are equal. In this case also, the range will be same. So the ratio is 1 : 1.

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