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Motion in A Plane question

2010 · Q100
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Motion in A Plane question

2010 · Q100

NEETPhysicsMotion in A PlaneMCQ+4 / −1
The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is
  1. A
    60o
  2. B
    15o
  3. C
    30o
  4. D
    45o
View written solutionFree

Correct answer: A

Let v be velocity of a projectile at maximum height H.

AIPMT 2010 Mains Physics - Motion in a Plane Question 33 English Explanation

v = ucosθ\theta θ

According to given problem, v=u2v = {u \over 2}v=2u​

∴\therefore∴ u2=ucos⁡θ⇒cos⁡θ=12⇒θ=60∘{u \over 2} = u\cos \theta \Rightarrow \cos \theta = {1 \over 2} \Rightarrow \theta = 60^\circ 2u​=ucosθ⇒cosθ=21​⇒θ=60∘

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