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Motion in A Plane question

2005 · Q157
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Motion in A Plane question

2005 · Q157

NEETPhysicsMotion in A PlaneMCQ+4 / −1
If the angle between the vectors A→\overrightarrow AA and B→\overrightarrow BB is θ\thetaθ, the value of the product (B→×A→).A→\left( {\overrightarrow B \times \overrightarrow A } \right).\overrightarrow A(B×A).A is equal to
  1. A
    BA2sinθ\thetaθ
  2. B
    BA2cosθ\thetaθ
  3. C
    BA2sinθ\thetaθcosθ\thetaθ
  4. D
    zero.
View written solutionFree

Correct answer: D

AIPMT 2005 Physics - Motion in a Plane Question 25 English Explanation

Let A→×B→=C→\overrightarrow A \times \overrightarrow B = \overrightarrow C A×B=C
The cross product of B→\overrightarrow B B and A→\overrightarrow A A is perpendicular to the plane containing A→\overrightarrow A A and B→\overrightarrow B B
i.e. perpendicular to B→\overrightarrow B B

If a dot product of this cross product and A→\overrightarrow A A is taken, as
the cross product is perpendicular to A→\overrightarrow A A, C→\overrightarrow C C ×\times× A→\overrightarrow A A = 0

Therefore product of (A→×B→)×A→=0\left( {\overrightarrow A \times \overrightarrow B } \right) \times \overrightarrow A = 0(A×B)×A=0

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