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Laws of Motion question

2002 · Q155
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Laws of Motion question

2002 · Q155

NEETPhysicsLaws of MotionMCQ+4 / −1
A block of mass 10 kg placed on rough horizontal surface having coefficient of friction m = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be
  1. A
    10 m/s2
  2. B
    5 m/s2
  3. C
    15 m/s2
  4. D
    0.5 m/s2.
View written solutionFree

Correct answer: B

AIPMT 2002 Physics - Laws of Motion Question 31 English Explanation
m = 10 kg, R = mg

$ \therefore $ Frictional force = fk

= $${\mu _k}R = {\mu _k}mg$$

= 0.5 × 10 × 10

= 50 N [g = 10 m/sec2]

$ \therefore $ Net force acting on the body = F = P – fk
= 100 – 50 = 50 N.

$ \therefore $ Acceleration of the block = a = F/m
= 50/10 = 5 m/sec2 .
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