NEETPhysicsLaws of MotionMCQ+4 / −1
Two masses as shown in the figure are suspended from a massless pulley. The acceleration of the system when masses are left free is


- A
- B
- C
- D.
View written solutionFree
Correct answer: B

$ \therefore $ 10g – T = 10a ....(i)
T – 5g = 5a ....(ii)
Adding (i) and (ii),
$$5g = 15a \Rightarrow a = {g \over 3}m/{s^2}$$
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