NEETPhysicsLaws of MotionMCQ+4 / −1
On the horizontal surface of a truck a block of mass 1 kg is placed (m = 0.6) and truck is moving with acceleration 5 m/sec2 then the frictional force on the block will be
- A5 N
- B6 N
- C5.88 N
- D8 N
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Correct answer: A
Maximum friction force = mg
= .6 × 1 × 9.8 = 5.88 N
But here required friction force
= ma = 1 × 5 = 5 N
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