NEETPhysicsLaws of MotionMCQ+4 / −1
A box of mass is pulled by a cord, up along a frictionless plane inclined at with the horizontal. The tension in the cord is . The acceleration of the box is (Take )
- A
- BZero
- C
- D
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Correct answer: D
$T-M g \sin 30=M a$

$$\begin{aligned} \& 30-5 \times 10 \times \frac{1}{2}=5 a \\ \& a=1 \mathrm{~m} / \mathrm{s}^2 \end{aligned}$$
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